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Physics Gravitation Kepler’s laws of Planetary Motion Single Correct MCQ
Published on: September 12, 2026

The ratio of the distances of two planets from the sun is 1.38. The ratio of their period of revolution around the sun is

A
1.38
B
$1.38^{\frac{3}{2}}$
C
$1.38^{1/2}$
D
$1.38^{3}$

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Text Solution

Verified by Experts
The correct answer is:
B
To find the ratio of the periods of revolution of two planets around the sun, we can use Kepler's Third Law of planetary motion, which states that the square of the period of revolution (T) of a planet is directly proportional to the cube of the semi-major axis (r) of its orbit. This can be expressed mathematically as:
$$ T^2 \propto r^3 $$
For two planets, we can write:
$$ \frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3} $$
Given that the ratio of the distances (r) is 1.38, we have:
$$ \frac{r_1}{r_2} = 1.38 $$
Therefore:
$$ \frac{T_1^2}{T_2^2} = (1.38)^3 $$
Thus, to find the ratio of the periods (T1 and T2), we take the square root:
$$ \frac{T_1}{T_2} = \sqrt{(1.38)^3} $$
This can be represented as option B. Therefore, option B represents the correct mathematical ratio.

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