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CGP EDU Academic Team
Published on: September 12, 2026
Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is
Text Solution
Verified by ExpertsThe correct answer is:
A
$\Delta P = \frac{4T}{r} \Rightarrow \frac{\Delta P_1}{\Delta P_2} = 4$ $\cdot \frac{r_2}{r_1} = 4$
and $\frac{V_1}{V_2} = \left(\frac{r_1}{r_2}\right)^3 = \frac{1}{64}$
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