Published by:
CGP EDU Academic Team
Published on: September 12, 2026
If pressure at half the depth of a lake is equal to 2/3 pressure at the bottom of the lake then what is the depth of the lake
Text Solution
Verified by ExpertsThe correct answer is:
B
Pressure at half the depth $= P_0 + \frac{h}{2} dg$
Pressure at the bottom =P_0 + hdg
According to given condition
$P_0 + \frac{h}{2} dg = \frac{2}{3} (P_0 + hdg)$
⇒ ⇒ $3P_0 + \frac{3h}{2} dg = 2P_0 + 2hdg$
$\Rightarrow h = \frac{2P_0}{dg} = \frac{2 \times 10^5}{10^3 \times 10} = 20 \ m$
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