A

Step 1: Understand capillarity. The height to which a liquid rises in a capillary tube is given by the formula:
$$ h = \frac{2\gamma \cos\theta}{\rho g r} $$
where:
- $h$ is the height of the liquid column,
- $\gamma$ is the surface tension of the liquid,
- $\theta$ is the contact angle,
- $\rho$ is the density of the liquid,
- $g$ is the acceleration due to gravity,
- $r$ is the radius of the capillary tube.

Step 2: Compare the two capillary tubes. Since both tubes A and B are dipped in the same liquid and have the same surface tension, density, and contact angle, the significant difference is the radius.

Step 3: Analyze the equation. As the radius $r$ increases, the height $h$ of the liquid column decreases. Thus, the smaller the radius, the higher the rise of liquid in the capillary tube.

Step 4: Since RA < RB, it follows that the liquid will rise higher in tube A compared to tube B.

Therefore, the correct answer is Option A: Water rises more in A than B.