A metal ball immersed in alcohol weighs 
at 0°C and 
at 59°C. The coefficient of cubical expansion of the metal is less than that of alcohol. Assuming that the density of metal is large compared to that of alcohol, it can be shown that
Text Solution
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As the coefficient of cubical expansion of metal is less as compared to the coefficient of
cubical expansion of liquid, we may neglect the expansion of metal ball. So when the ball is immersed in alcohol at 0ºC, it displaces some volume V of alcohol at 0ºC and has weight W 1 .
W 1 = W 0 – V ρ ρ 0 g
where W 0 = weight of ball in air
Similarly, W 2 = W 0 – V ρ ρ 50 g
where ρ ρ 0 = density of alcohol at 0ºC
and ρ ρ 50 = density of alcohol at 50ºC
As ρ ρ 50 < ρ ρ 0 , ⇒ ⇒ W 2 > W 1 or W 1 < W 2
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