A glass flask is filled up to a mark with 50 cc of mercury at 18ºC. If the flask and contents are heated to 38ºC, how much mercury will be above the mark? (α for glass is 9 × 10 –6 /ºC and coefficient of real expansion of mercury is 180 × 10 –6 /ºC)
Text Solution
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Due to volume expansion of both mercury and flask, the change in volume of mercury relative
to flask is given by $\Delta V = V_{o}[\gamma_{L} - \gamma_{g}]\Delta \theta = \bar{V}[\gamma_{m} - 3 \alpha_{g}]\Delta \theta$
$= 50[180 \times 10^{-6} - 3 \times 9 \times 10^{-6}](38 - 18) = 0.153cc$
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