Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A gas for which $\gamma = 1.5$ is suddenly compressed to $\frac{1}{4}$ th of the initial volume. Then the ratio of the final to the initial pressure is
Text Solution
Verified by ExpertsThe correct answer is:
D
$\mathrm{P}_1 \mathrm{V}_1^{\gamma} = \mathrm{P}_2 \mathrm{V}_2^{\gamma} \Rightarrow \frac{\mathrm{P}_2}{\mathrm{P}_1} = \left[\frac{\mathrm{V}_1}{\mathrm{V}_2}\right]^{\gamma} = \left[\frac{4}{1}\right]^{3/2} = \frac{8}{1}$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If a cylinder containing a gas at high pressure explodes, the gas undergoes
The work done in an adiabatic change in a gas depends only on
In adiabatic expansion
The pressure in the tyre of a car is four times the atmospheric pressure at 300 K. If this tyre sud…
A monoatomic gas $(\gamma = 5/3)$ is suddenly compressed to $\frac{1}{8}$ of its original volume ad…