Published by:
CGP EDU Academic Team
Published on: September 12, 2026
One mole of an ideal gas with $\gamma = 1.4$ , is adiabatically compressed so that its temperature rises from $27^\circ C$ to $35^\circ \mathrm{C}$ . The change in the internal energy of the gas is ( $R = 8.3 \text{ J/mol.K}$ )
Text Solution
Verified by ExpertsThe correct answer is:
B
Change in internal energy of the gas
$\Delta U = - \Delta W \frac{R}{\gamma - 1} \left[ T_2 - T_1 \right] = \frac{8.3}{(1.4 - 1)} [308 - 300] = 166J$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If a cylinder containing a gas at high pressure explodes, the gas undergoes
The work done in an adiabatic change in a gas depends only on
In adiabatic expansion
The pressure in the tyre of a car is four times the atmospheric pressure at 300 K. If this tyre sud…
A monoatomic gas $(\gamma = 5/3)$ is suddenly compressed to $\frac{1}{8}$ of its original volume ad…