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CGP EDU Academic Team
Published on: September 12, 2026
Adiabatic modulus of elasticity of a gas is $2.1 \times \frac{10^{5} \mathrm{N}}{\mathrm{m}^{2}}$ What will be its isothermal modulus of elasticity $\left(\frac{c_p}{c_v} = 1.4\right)$
Text Solution
Verified by ExpertsThe correct answer is:
B
$\frac{\text{Adiabatic elasticity (E}_{\varphi}\text{)}}{\text{Isothermal elasticity (E}_{\theta}\text{)}} = \gamma \Rightarrow \text{E}_{\theta} = \frac{\text{E}_{\varphi}}{\gamma} \Rightarrow \text{E}_{\theta} = \frac{2.1 \times 10^{5}}{1.4} = 1.5 \times 10^{5} \text{N/m}^{2}$
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