Published by:
CGP EDU Academic Team
Published on: September 12, 2026
For an adiabatic expansion of a perfect gas, the value of $\frac{\Delta P}{P}$ is equal to (a) $-\sqrt{\gamma} \frac{\Delta V}{V}$ (b) $-\frac{\Delta V}{V}$ (c) $-\gamma \frac{\Delta V}{V}$ (d) $-\gamma^{2} \frac{\Delta V}{V}$
Text Solution
Verified by ExpertsThe correct answer is:
C
$PV^{\gamma} =$ constant: Differentiating both sides
$P_{\gamma}V^{\gamma-1}dV + V^{\gamma}dP = 0 \Rightarrow \frac{dP}{P} = -\gamma \frac{dV}{V}$
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