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CGP EDU Academic Team
Published on: September 12, 2026
A carnot engine has the same efficiency between 800 K to 500 K and x K to 600 K. The value of x is
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Verified by ExpertsThe correct answer is:
B
In first case, $(\eta_1) = 1 - \frac{500}{800} = \frac{3}{8}$ and in second case, $(\eta_2) = 1 - \frac{600}{x}$ Since $\eta_1 = \eta_2$, therefore $\frac{3}{8} = 1 - \frac{600}{x}$ or $\frac{600}{x} = 1 - \frac{3}{8} = \frac{5}{8}$ or $x = \frac{600 \times 8}{5} = 960 \mathrm{K}$
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