Published by:
CGP EDU Academic Team
Published on: September 12, 2026
An ideal heat engine working between temperature T 1 and T 2 has an efficiency η η , the new efficiency if both the source and sink temperature are doubled, will be
$(a) \frac{\eta}{2} (c) 2\eta (b) \eta (d) 3\eta$
Text Solution
Verified by ExpertsThe correct answer is:
B
In first case $\eta_1 = \frac{\mathrm{T}_1 - \mathrm{T}_2}{\mathrm{T}_1}$ In second case $\eta_2 = \frac{2\mathrm{T}_1 - 2\mathrm{T}_2}{2\mathrm{T}_1} = \frac{\mathrm{T}_1 - \mathrm{T}_2}{\mathrm{T}_1} = \eta$
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