Published by:
CGP EDU Academic Team
Published on: September 12, 2026
An ideal gas heat engine operates in Carnot cycle between 227°C and 127°C. It absorbs $6 \times 10^{4}$ cals of heat at higher temperature. Amount of heat converted to work is
Text Solution
Verified by ExpertsThe correct answer is:
C
$\eta = \frac{T_1 - T_2}{T_1} = \frac{W}{Q} \Rightarrow W = \frac{Q(T_1 - T_2)}{T_1}$ $= \frac{6 \times 10^4 [(227 + 273) - (273 + 127)]}{(227 + 273)}$ $= \frac{6 \times 10^4 \times 100}{500} = 1.2 \times 10^4 \mathrm{cal}$
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