Two rectangular blocks A and B of different metals have same length and same area of cross-section. They are kept in such a way that their cross-sectional area touch each other. The temperature at one end of A is 100°C and that of B at the other end is 0°C. If the ratio of their thermal conductivity is 1 : 3, then under steady state, the temperature of the junction in contact will be
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It is given that $\frac{K_1}{K_2} = \frac{1}{3} \Rightarrow K_1 = K \text{ then } K_2 = 3K$ the temperature of the junction in contact $\theta = \frac{K_1 \theta_1 + K_2 \theta_2}{K_1 + K_2} = \frac{1 \times 100 + 3 \times 0}{1 + 3} = \frac{100}{4} = 25^\circ C$
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