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CGP EDU Academic Team
Published on: September 12, 2026
Consider two hot bodies $\mathbf{B}_1$ and $\mathbf{B}_{2}$ which have temperatures 100^\circ C and $80^\circ C$ respectively at $t=0$ . The temperature of the surroundings is $40^\circ C$ . The ratio of the respective rates of cooling $R_1$ and $R_2$ of these two bodies at $t=0$ will be
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Verified by ExpertsThe correct answer is:
A
Initially at t = 0
Rate of cooling (R) ∝ ∝ Fall in temperature of body ( θ θ – θ θ 0 )
⇒ ⇒ $\frac{R_1}{R_2} = \frac{\theta_1 - \theta_0}{\theta_2 - \theta_0} = \frac{100 - 40}{80 - 40} = \frac{3}{2}$
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