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CGP EDU Academic Team
Published on: September 12, 2026
In Newton's experiment of cooling, the water equivalent of two similar calorimeters is 10 gm each. They are filled with 350 gm of water and 300 gm of a liquid (equal volumes) separately. The time taken by water and liquid to cool from $70^\circ \mathrm{C}$ to $60^\circ \mathrm{C}$ is 3 min and 95 sec respectively. The specific heat of the liquid will be
Text Solution
Verified by ExpertsThe correct answer is:
C
$s_{1} = \frac{1}{m_{1}} \left[ \frac{t}{t_{W}} (m_{W} C_{W} + W) - W \right]$
$= \frac{1}{300} \left[ \frac{95}{3 \times 60} (350 \times 1 + 10) - 10 \right]$ =0.6 Cal/gm × × °C
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