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CGP EDU Academic Team
Published on: September 12, 2026
A particle executing S.H.M. of amplitude 4 cm and T = 4 sec. The time taken by it to move from positive extreme position to half the amplitude is
Text Solution
Verified by ExpertsThe correct answer is:
C
Equation of motion $y = a \cos \omega t$
$\Rightarrow \frac{a}{2} = a \cos \omega t \Rightarrow \cos \omega t = \frac{1}{2} \Rightarrow \omega t = \frac{\pi}{3}$ $\Rightarrow \frac{2 \pi t}{T} = \frac{\pi}{3} \Rightarrow t = \frac{\frac{\pi}{3} \times T}{2 \pi} = \frac{4}{3 \times 2} = \frac{2}{3} \text{ sec}$
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