A particle of mass 10 gm is describing S.H.M. along a strai…

Physics Simple Harmonic Motion (Oscillations) Energy of Simple Harmonic Motion Single Correct MCQ

Published on: September 12, 2026

A particle of mass 10 gm is describing S.H.M. along a straight line with period of 2 sec and amplitude of 10 cm. Its kinetic energy when it is at 5 cm from its equilibrium position is

$37.5 \pi^{2} \text{ ergs}$

$3.75\pi^{2}\text{ergs}$

$375\pi^{2}$ ergs

$0.375\pi^{2}\text{ergs}$

Text Solution

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The correct answer is:

Kinetic energy $\mathbf{K} = \frac{1}{2} m \omega^{2} (a^{2} - y^{2})$

$= \frac{1}{2} \times 10 \times \left(\frac{2 \pi}{2}\right)^2 \left[10^2 - 5^2\right] = 375 \pi^2 \text{ ergs}$

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