Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A particle executes simple harmonic motion with a frequency f. The frequency with which its kinetic energy oscillates is
Text Solution
Verified by ExpertsThe correct answer is:
C
For a particle executing SHM the displacement equation is given by
$y = a \sin \omega t = a \sin 2 \pi f t.$
$kinetic energy KE = \frac{1}{2} mv^{2} = \frac{1}{2} m \left(\frac{dy}{dt}\right)^{2} where \frac{dy}{dt} = 2 \pi f a \cos 2 \pi f t \therefore KE = \frac{1}{2} m \{(2 \pi f a)^{2} \cos^{2} 2 \pi f t\} KE \propto (1 + \cos 4 \pi f t) \cos 4 \pi f t changes periodically with frequency 2f.$
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