The periodic time of a simple pendulum of length 1 m and amplitude 2 cm is 5 seconds. If the amplitude is made 4 cm, its periodic time in seconds will be
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In the question we are given the length of the pendulum, l = 1 m
Amplitude of the pendulum, $A = 2 \text{ cm}$
And the time period of this pendulum, $T = 5$ seconds.
We have to find the time period of this pendulum, when its amplitude becomes 4 cm .
We know, time period of a simple pendulum is given by the equation, $T = 2 \pi \sqrt{\frac{l}{g}}$ , where ' 1 ' is the length of the pendulum and ' g ' is acceleration due to gravity.
From this equation, it is clear that the time period of a simple pendulum does not depend on its amplitude.
In the question, we change the amplitude of the pendulum from 2 cm to 4 cm . Length of the pendulum remains the same and acceleration due to gravity; ' g ' is a constant.
Therefore, the time period of the pendulum when its amplitude = 4 cm , length ' 1 ' = 1 m will be 5 seconds.
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