Tuning fork 
has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork 
. When 
is loaded with wax, it still produces 6 beats/second with 
. The frequency of 
before loading was
Text Solution
Verified by ExpertsThe correct answer is:
B
n A = Known frequency = 256 Hz, n B =?
x = 6 bps, which remains the same after loading.
Unknown tuning fork F 2 is loaded so n B ↓ ↓
Hence n A – n B ↓ ↓ = x ... (i) Wrong
n B ↓ ↓ – n A = x ... (ii) Correct
⇒ ⇒ n B = n A + x = 256 + 6 = 262 Hz.
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