Two tuning forks A and B give 4 beats per second. The frequency of A is 256 Hz. On loading B slightly, we get 5 beats in 2 seconds. The frequency of B after loading is
Text Solution
Verified by ExpertsThe correct answer is:
C
n A = Known frequency = 256 Hz, n B =?
x = 4 beats per sec which is decreasing (4 bps to 
) after loading (i.e. x ↓ ↓ )
Unknown tuning fork B, is loaded so n B ↓ ↓
Hence n A – n B ↓ ↓ = x ↓ ↓ ... (i) Wrong
n B ↓ ↓ – n A = x ↓ ↓ ... (ii) Correct
⇒ ⇒ n B = n A + x = 256 + 4 = 260 Hz.
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