A tuning fork arrangement (pair) produces 4 beats/sec with one fork of frequency 288 cps. A little wax is placed on the unknown fork and it then produces 2 beats/sec. The frequency of the unknown fork is
Text Solution
Verified by ExpertsThe correct answer is:
B
n A = Known frequency = 288 cps, n B = ?
x = 4 bps, which is decreasing (from 4 to 2) after loading i.e. x ↓ ↓
Unknown fork is loaded so n B ↓ ↓
Hence n A – n B ↓ ↓ = x ↓ ↓ Wrong
n B ↓ ↓ – n A ↓ ↓ = x ↓ ↓ Correct
⇒ ⇒ n B = n A + x = 288 + 4 = 292 Hz.
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