Two strings X and Y of a sitar produce a beat frequency 4 Hz. When the tension of the string Y is slightly increased the beat frequency is found to be 2 Hz. If the frequency of X is 300 Hz, then the original frequency of Y was
Text Solution
Verified by ExpertsA
$n_x = 300 \mathrm{Hz},$ n_y = ?
x = beat frequency = 4 Hz, which is decreasing (4 → → 2)
after increasing the tension of the string y.
Also tension of wire y increasing so $n_y \uparrow$ $(\therefore \mathrm{n} \propto \sqrt{\mathrm{T}})$
Hence $n_x - n_y \downarrow = x \downarrow$ Correct
$n_y \uparrow - n_x = x \downarrow$ Wrong
⇒ ⇒ $n_y = n_x - x = 300 - 4 = 296 \mathrm{Hz}$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems