A source of sound is moving with constant velocity of 20 m/s emitting a note of frequency 1000 Hz. The ratio of frequencies observed by a stationary observer while the source is approaching him and after it crosses him will be (Speed of sound v = 340 m/s)
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When source is approaching the observer, the frequency heard
$n_a = \left(\frac{v}{v - v_s}\right) \times n = \left(\frac{340}{340 - 20}\right) \times 1000 = 1063 \mathrm{Hz}$ When source is receding, the frequency heard $n_r = \left(\frac{v}{v + v_s}\right) \times n = \frac{340}{340 + 20} \times 1000 = 944$ $\Rightarrow n_a : n_r = 9 : 8$
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