Two whistles A and B produces notes of frequencies 660 Hz and 596 Hz respectively. There is a listener at the mid-point of the line joining them. Now the whistle B and the listener start moving with speed 30 m/s away from the whistle A. If speed of sound be 330 m/s, how many beats will be heard by the listener
Text Solution
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For observer note of B will not change due to zero relative motion.
Observed frequency of sound produced by A
$= 660 \frac{(330-30)}{330} = 600Hz$
$\begin{matrix} \bullet \\ \bullet & \bullet \end{matrix}$ No. of beats = 600 – 596 = 4
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