Two identical straight wires are stretched so as to produce 6 beats per second when vibrating simultaneously. On changing the tension in one of them, the beat frequency remains unchanged. Denoting by $T_1, T_2$ , the higher and the lower initial tensions in the strings, then it could be said that while making the above change in tension
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Using $n = \frac{1}{2l} \sqrt{\frac{T}{m}}$ ;
As $T_1 > T_2$ ⇒ ⇒ $n_1 > n_2$ giving $n_{1} - n_{2} = 6$
The beat frequency of 6 will remain fixed when
(i) $n_1$ remains same but n₂ is increased to a new value $(n_{2}' - n_{2} = 12)$ by increasing tension $T_{2}$ .
(ii) n 2 remains same but n 1 is decreased to a new value $(n_{1} - n_{1}^{\prime} = 12)$ by decreasing tension T 1 .
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