A stone is hung in air from a wire which is stretched over a sonometer. The bridges of the sonometer are L cm apart when the wire is in unison with a tuning fork of frequency N. When the stone is completely immersed in water, the length between the bridges is l cm for re-establishing unison, the specific gravity of the material of the stone is
Text Solution
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Frequency of vib. is stretched string 
When the stone is completely immersed in water, length changes but frequency doesn’t ( 
unison reestablished)
Hence length 
⇒ ⇒ 
(Density of stone = ρ ρ and density of water =1)
⇒ ⇒ 
⇒ ⇒ 
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