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Physics Wave and Sound Mix MCQ (Single Correct)

There are three sources of sound of equal intensity with frequencies 400, 401 and 402 vib/sec. The number of beats heard per second is

A
0
B
1
C
2
D
3

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Text Solution

Verified by Experts
The correct answer is:
B

Let n – 1 (= 400), n (= 401) and n + 1 (= 402) be the frequencies of the three waves. If a be the amplitude of each then and

Resultant displacement due to all three waves is

⇒ ⇒

This is the resultant wave having amplitude

For maximum amplitude cos 2 π π t = 1 ⇒ ⇒ 2 π π t = 2m π π where m = 0, 1, 2, 3, ...

⇒ ⇒ t = 0, 1, 2, 3 ...

Hence time interval between two successive maximum is 1 sec. So beat frequency = 1

Also for minimum amplitude (2cos 2 π π t) = 0

Hence time interval between two successive minima is 1 sec so, number of beats per second = 1

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