In Melde's experiment, the string vibrates in 4 loops when a 50 gram weight is placed in the pan of weight 15 gram. To make the string to vibrates in 6 loops the weight that has to be removed from the pan is
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Frequency of vibration of string is given by
$n = \frac{p}{2l} \sqrt{\frac{T}{m}}$
⇒ ⇒ $p \sqrt{T} =$ constant
⇒ ⇒ $\frac{p_1}{p_2} = \sqrt{\frac{T_2}{T_1}}$
Hence $\frac{4}{6} = \sqrt{\frac{T_2}{(50+15) \text{ gm-force}}}$
⇒ ⇒ $T_{2} = 28.8gm - f$
Hence weight removed from the pan
$= T_{1} - T_{2} = 65 - 28.8 = 36.2$ gm-force = 0.036 kg-f.
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