A tuning fork A produces 4 beats/sec with another tuning fork B of frequency 320 Hz. On filing the fork A, 4 beats/sec are again heard. The frequency of fork A, after filing is
Text Solution
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n A = ?, n B = Known frequency = 320 Hz
x = 4 bps, which remains same after filing.
Unknown fork A is filed so n A
Hence n A – n B = x Wrong
n B – n A = x Correct
⇒ ⇒ n A = n B – x = 320 – 4 = 316 Hz.
This is the frequency before filing.
But in question frequency after filing is asked which must be greater than 316 Hz, such that it produces 4 beats per sec. Hence it is 324 Hz.
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