The charges on two sphere are +7 μ μ C and – 5 μ μ C respectively. They experience a force F. If each of them is given and additional charge of – 2 μ μ C, the new force of attraction will be
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$\mathbf{F} = \frac{1}{4 \pi \varepsilon_0} \frac{(+7 \times 10^{-6})(-5 \times 10^{-6})}{r^2}$ $= - \frac{1}{4 \pi \varepsilon_0} \frac{35 \times 10^{12}}{r^2} \mathrm{N}$ $\mathbf{F}' = \frac{1}{4 \pi \varepsilon_0} \frac{(+5 \times 10^{-6})(-7 \times 10^{-6})}{r^2}$ $= - \frac{1}{4 \pi \varepsilon_0} \frac{35 \times 10^{12}}{r^2} \mathrm{N}$
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