Two point charges 3 × × 10 –6 C and 8 × × 10 –6 C repel each other by a force of 6 × × 10 –3 N. If each of them is given an additional charge – 6 × × 10 6 C, the force between them will be
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$F \propto Q_1 Q_2$ ⇒ ⇒ $\frac{F_1}{F_2} = \frac{Q_1 Q_2}{Q_1' Q_2'}$
$= \frac{3 \times 10^{-6} \times 8 \times 10^{-6}}{(3 \times 10^{-6} - 6 \times 10^{-6})(8 \times 10^{-6} - 6 \times 10^{-6})} = \frac{3 \times 8}{-3 \times 2} = -\frac{4}{1}$
⇒ ⇒ $F_{2} = -\frac{F_{1}}{4} = -\frac{6 \times 10^{-3}}{4} = -1.5 \times 10^{-3} \, \mathrm{N}$ (Attractive)
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