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CGP EDU Academic Team
Published on: September 12, 2026
Two identical metal balls at temperature $200^{\circ}C$ and 400^\circ C kept in air at 27^\circ C . The ratio of net heat loss by these bodies is
Text Solution
Verified by ExpertsThe correct answer is:
D
If temperature of surrounding is considered then
net loss of energy of a body by radiation $Q = A \varepsilon \sigma (T^4 - T_0^4) t \Rightarrow Q \propto (T^4 - T_0^4) \Rightarrow \frac{Q_1}{Q_2} = \frac{T_1^4 - T_0^4}{T_2^4 - T_0^4}$
$=\frac{(273+200)^4-(273+27)^4}{(273+400)^4-(273+27)^4}=\frac{(473)^4-(300)^4}{(673)^4-(300)^4}$
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