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CGP EDU Academic Team
Published on: September 12, 2026
A black body is heated from $27^\circ C$ to $127^\circ \mathrm{C}$ . The ratio of their energies of radiations emitted will be
Text Solution
Verified by ExpertsThe correct answer is:
D
$\frac{Q_1}{Q_2} = \frac{T_1^4}{T_2^4} = \left(\frac{273+27}{273+127}\right)^4 = \left(\frac{300}{400}\right)^4 = \frac{81}{256}$
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