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CGP EDU Academic Team
Published on: September 12, 2026
A body of mass 1kg is executing simple harmonic motion. Its displacement $y(\mathrm{cm})$ at t seconds is given by $y = 6 \sin(100t + \pi/4)$ . Its maximum kinetic energy is
Text Solution
Verified by ExpertsThe correct answer is:
B
So $a = 6cm, \omega = 100 \mathrm{rad}/\mathrm{sec}$
$K_{\max} = \frac{1}{2} m \omega^2 a^2 = \frac{1}{2} \times 1 \times (100)^2 \times (6 \times 10^{-2})^2 = 18 \text{ J}$
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