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CGP EDU Academic Team
Published on: September 12, 2026
Fig. below shows the wave $y = A \sin(\omega t - kx)$ at any instant travelling in the +ve x-direction. What is the slope of the curve at B
Text Solution
Verified by ExpertsThe correct answer is:
C
The particle velocity is maximum at B and is given by $\frac{\mathrm{dy}}{\mathrm{dt}} = (\mathrm{v_p})_{\max} = \omega A$ Also wave velocity is $\frac{\mathrm{dx}}{\mathrm{dt}} = v = \frac{\omega}{k}$ So slope $\frac{\mathrm{dy}}{\mathrm{dx}} = \frac{(\mathrm{v_p})_{\max}}{v} = kA$
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