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CGP EDU Academic Team
Published on: September 12, 2026
When a wave travels in a medium, the particle displacement is given by $y(x,t) = 0.03 \sin \pi (2t - 0.01x)$ where y and x are meters and t in seconds. The phase difference, at a given instant of time between two particle 25 m. apart in the medium, is
$(a) \frac{\pi}{8} \quad (b) \frac{\pi}{4} \quad (c) \frac{\pi}{2} \quad (d) \pi$
Text Solution
Verified by ExpertsThe correct answer is:
B
$y(x,t) = 0.03 \sin \pi (2t - 0.01x)$ $= 0.03 \sin(2 \pi t - 0.01 \pi x)$
$k=0.01\pi=\frac{2\pi}{\lambda}$
⇒ ⇒ $\Delta \varphi = \frac{2 \pi}{\lambda} \Delta x = 0.01 \pi \times 25 = \frac{\pi}{4}$
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