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CGP EDU Academic Team
Published on: September 12, 2026
Three charges $4q, Q$ and $\alpha$ are in a straight line in the position of 0, 1/2 and / respectively. The resultant force on $\alpha$ will be zero, if $Q=$
Text Solution
Verified by ExpertsThe correct answer is:
A
The force between 4q and q; $F_1 = \frac{1}{4 \pi \epsilon_0} \cdot \frac{4q \times q}{l^2}$
The force between Q and q; $F_2 = \frac{1}{4 \pi \varepsilon_0} \cdot \frac{Q \times q}{(l/2)^2}$
We want $F_1 + F_2 = 0$ or $\frac{4q^{2}}{l^{2}} = - \frac{4Qq}{l^{2}}$ ⇒ ⇒ $Q = -q$
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