Electric charges of $1 \mu C, -1 \mu C$ and $2 \mu C$ are placed in air at the corners A, B and C respectively of an equilateral triangle ABC having length of each side 10 cm. The resultant force on the charge at C is
Text Solution
Verified by ExpertsB
F A = force on C due to charge placed at A
$=9 \times 10^{9} \times \frac{10^{-6} \times 2 \times 10^{-6}}{(10 \times 10^{-2})^{2}} = 1.8 \mathrm{N}$
F B = force on C due to charge placed at B
$= 9 \times 10^{9} \times \frac{10^{-6} \times 2 \times 10^{-6}}{(0.1)^{2}} = 1.8 N$
Net force on C
$F_{net} = \sqrt{(F_A)^2 + (F_B)^2 + 2 F_A F_B \cos 120^\circ} = 1.8\, \mathrm{N}$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems