Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two small conducting spheres of equal radius have charges $+10 \mu C$ and $-20 \mu C$ respectively and placed at a distance $R_D$ from each other experience force $F_1$ . If they are brought in contact and separated to the same distance, they experience force $F_2$ . The ratio of $F_1$ to $F_2$ is
Text Solution
Verified by ExpertsThe correct answer is:
B
$F \propto Q_1 Q_2$ ⇒ ⇒ $\frac{F_1}{F_2} = \frac{Q_1 Q_2}{Q_3 Q_2} = \frac{10 \times -20}{-5 \times -5} = \frac{8}{1}$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The law, governing the force between electric charges is known as
When the distance between the charged particles is halved, the force between them becomes
There are two charges +1 microcoulombs and +5 microcoulombs. The ratio of the forces acting on them…
A charge q 1 exerts some force on a second charge q 2 . If third charge q 3 is brought near, the fo…
$F_g$ and $F_e$ represents gravitational and electrostatic force respectively between electrons sit…
The ratio of the forces between two small spheres with constant charge (a) in air $(b)$ in a medium…