Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two metal pieces having a potential difference of 800 V are 0.02 m apart horizontally. A particle of mass $1.96 \times 10^{-15} \, \mathrm{kg}$ is suspended in equilibrium between the plates. If e is the elementary charge, then charge on the particle is
Text Solution
Verified by ExpertsThe correct answer is:
B
For equilibrium mg = qE
∴ ∴ $1.96 \times 10^{-15} \times 9.8 = q \times \left(\frac{800}{0.02}\right)$
⇒ ⇒ $q = \frac{1.96 \times 10^{-15} \times 9.8 \times 0.02}{800}$
⇒ ⇒ $n \times 1.6 \times 10^{-19} = \frac{1.96 \times 10^{-15} \times 9.8 \times 0.02}{800}$ ⇒ ⇒ n = 3.
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