The acceleration of an electron in an electric field of mag…

Physics Electrostatics Potential & Capacitance Electric Field and Potential,Defference,Energy and Dipole Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: September 12, 2026

The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is $1.76 \times 10^{11}$ C/kg, is

$8.8 \times 10^{14}$ m/sec 2

$6.2 \times 10^{13}$ m/sec 2

$5.4 \times 10^{12}$ m/sec 2

Zero

Text Solution

Verified by Experts

The correct answer is:

$a = \frac{eE}{m} \Rightarrow a = 1.76 \times 10^{11} \times 50 \times 10^{2}$

$= 8.8 \times 10^{14} m/sec^{2}$

Previous Question Next Question

Get practice questions, solutions, and test series in one place.

Share your experience with this question and solution.

Send your comment, doubt, correction, or feedback to admin.

What students say about this solution

No reviews yet. Be the first to write a review.