Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Three charges $Q, (+q)$ and (+q) are placed at the vertices of an equilateral triangle of side l as shown in the figure. If the net electrostatic energy of the system is zero, then Q is equal to
Text Solution
Verified by ExpertsThe correct answer is:
A
Potential energy of the system
$U = k \frac{Qq}{l} + \frac{kq^{2}}{l} + \frac{kqQ}{l} = 0$
⇒ ⇒ $\frac{kq}{l}(Q + q + Q) = 0$ ⇒ ⇒ $Q = -\frac{q}{2}$
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A charge q is placed at the center of the line joining two equal charges Q. The system of the three…
Inside a hollow charged spherical conductor, the potential
Two small spheres each carrying a charge q are placed r meter apart. If one of the spheres is taken…
The electric charge in uniform motion produces
Two charged spheres of radii 10 cm and 15 cm are connected by a thin wire. No current will flow, if…
The electric field inside a spherical shell of uniform surface charge density is