The electric flux for Gaussian surface A that enclose the c…

Physics Electrostatics Potential & Capacitance Electric Flux and Gauss's Law Single Correct MCQ

Published on: September 12, 2026

The electric flux for Gaussian surface A that enclose the charged particles in free space is (given q 1 = –14 nC, q 2 = 78.85 nC, q 3 = – 56 nC)

10 3 Nm 2 C –1

10 3 CN -1 m –2

6.32 × × 10 3 Nm 2 C –1

6.32 × × 10 3 CN -1 m –2

Text Solution

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The correct answer is:

Flux is due to charges enclosed per $E_0$

∴ ∴ Total flux = $\left(-14 + 78.85 - 56\right) nC / \varepsilon_0$

$= 8.85 \times 10^{-9} C \times \frac{4 \pi}{4 \pi \varepsilon_0} = 8.85 \times 10^{-9} \times 9 \times 10^{9} \times 4 \pi$

$= 10004 \, Nm^{2} / C$ i..e. $1000 \, \mathrm{Nm^{2}C^{-1}}$

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