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CGP EDU Academic Team
Published on: September 12, 2026
The capacitance of an air capacitor is $15 \mu F$ the separation between the parallel plates is 6 mm . A copper plate of 3 mm thickness is introduced symmetrically between the plates. The capacitance now becomes
Text Solution
Verified by ExpertsThe correct answer is:
D
By using $C_{air} = \frac{\varepsilon_0 A}{d},$ $C_{medium} = \frac{\varepsilon_0 A}{d - t + \frac{t}{K}}$
For K = ∞ ∞ $C_{\text{medium}} = \frac{\varepsilon_0 A}{d - t}$
⇒ ⇒ $\frac{c_{m}}{c_{a}} = \frac{d}{d - t}$ ⇒ ⇒ $\frac{C_{m}}{15} = \frac{6}{6 - 3}$ ⇒ ⇒ $C_{m} = 30 \mu C$
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