The expression for the capacity of the capacitor formed by compound dielectric placed between the plates of a parallel plate capacitor as shown in figure, will be (area of plate = A)
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The given capacitor may be supposed to be formed of three component capacitors $C_1, C_2$ and $C_3$ connected in series.
$\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2} + \frac{1}{C_3} \\ = \frac{d_1}{AK_1 \epsilon_0} + \frac{d_2}{AK_2 \epsilon_0} + \frac{d_3}{AK_3 \epsilon_0} \\ C_s = \frac{\epsilon_0 A}{\frac{d_1}{K_1} + \frac{d_2}{K_2} + \frac{d_3}{K_3}}$
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