Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The energy required to charge a capacitor of $5 \mu F$ by connecting a d.c. source of 20 kV is
Text Solution
Verified by ExpertsThe correct answer is:
D
$U = \frac{1}{2} CV^{2} = \frac{1}{2} 5 \times 10^{-6} \times (20 \times 10^{3})^{2} = 1 kJ$
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