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CGP EDU Academic Team
Published on: September 12, 2026
The capacitance of a parallel plate capacitor is $12 \mu F$ . If the distance between the plates is doubled and area is halved, then new capacitance will be
Text Solution
Verified by ExpertsThe correct answer is:
D
$C = \frac{\varepsilon_0 A}{d}$ As A → → $\frac{1}{2}$ times and d → → 2 times
So $C \to \frac{1}{4}$ times i.e. $C' = \frac{1}{4} C = \frac{12}{4} = 3 \mu F$
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