Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A 10 μ μ F capacitor is charged to a potential difference of 1000 V. The terminals of the charged capacitor are
disconnected from the power supply and connected to the terminals of an uncharged 6 μ μ F capacitor. What is
the final potential difference across each capacitor
Text Solution
Verified by ExpertsThe correct answer is:
C
After charging, total charge on the capacitor Q = CV
= 10 × × 10 –6 F × × 1000 V = 10 –2 C.
Common potential $V = \frac{C_1 V_1}{C_1 + C_2}$ $\frac{10^{-2}}{16 \times 10^{-6}}$ = 625V.
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